C\u00f3 nhi\u1ec1u. Lo\u1ea1i l\u00f4 xi\u00ean. V\u00e0 c\u00e1ch ch\u01a1i. Kh\u00e1c nhau, tuy nhi\u00ean trong. S\u1ed1 \u0111\u00f3 l\u00f4 xi\u00ean 2 kh\u00e1 ph\u1ed5 bi\u1ebfn v\u00e0 \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi \u01b0a chu\u1ed9ng. Khi ch\u01a1i l\u00f4 xi\u00ean 2, b\u1ea1n ch\u1ec9 c\u1ea7n. Ch\u1ecdn ra 2 s\u1ed1 t\u1eeb 00-99 b\u1ea1n. Ngh\u0129 c\u00f3 kh\u1ea3 n\u0103ng. Cao v\u1ec1 v\u00e0 ghi xi\u00ean 2. N\u1ebfu h\u00f4m \u0111\u00f3. Soi th\u1ea5y. C\u1ea3 2 con s\u1ed1 n\u00e0y tr\u00f9ng v\u1edbi. C\u1eb7p \u0111u\u00f4i c\u1ee7a b\u1ea5t. K\u00ec gi\u1ea3i n\u00e0o trong SXKT th\u00ec ngh\u0129a l\u00e0 b\u1ea1n \u0111\u00e3 tr\u00fang. N\u1ebfu ch\u1ec9 v\u1ec1 1 trong 2 ho\u1eb7c. Kh\u00f4ng v\u1ec1 con. N\u00e0o th\u00ec \u0111\u1ec1u t\u00ednh. L\u00e0 kh\u00f4ng tr\u00fang. Sau \u0111\u00e2y s\u1ebd l\u00e0 m\u1ed9t s\u1ed1 h\u01b0\u1edbng d\u1eabn <\/span>c\u00e1ch. T\u00ednh l\u00f4 xi\u00ean 2<\/b> hi\u1ec7u qu\u1ea3. \u0110\u1ebfn t\u1eeb c\u00e1c cao th\u1ee7. Trong l\u00e0ng l\u00f4 \u0111\u1ec1 g\u1eedi \u0111\u1ebfn b\u1ea1n!<\/span><\/p>\n S\u1ed1 ti\u1ec1n khi b\u1ea1n tr\u00fang l\u00f4 xi\u00ean 2 \u1edf 3 mi\u1ec1n l\u00e0 kh\u00e1c nhau n\u00ean ta s\u1ebd \u0111i t\u00ecm hi\u1ec3u t\u1eebng v\u00f9ng mi\u1ec1n.<\/span><\/p>\nL\u00f4 xi\u00ean 2 \u0103n bao nhi\u00eau<\/b><\/h2>\n
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\nH\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2 \u0111\u01a1n gi\u1ea3n \u2013 Cao th\u1ee7 chia s\u1ebb<\/span><\/h1>\n
H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2 \u0111\u01a1n gi\u1ea3n \u2013 Cao th\u1ee7 chia s\u1ebb<\/span><\/h1>\n<\/div>\n<\/div>\n<\/p>\n<\/div>\n
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